Fedorchenko Mikhail Valerevich h ttps://www.p a t reon. co m/p o sts/sy llo g i sm- and -9842751 Updated periodically + Neural Interface Syllogism Modulation of Thinking
Subj e c t i v e P r oo f Experience Practice T h e o r y X Statemen P S Pr T h E x
The result of a syllogism depends on the particular logical operation. Assuming the scheme uses the standard AND operation, the results are as follows: - **\\( A = 0, B = 0 \) → 0** - **\\( A = 1, B = 0\) → 0** - **\\( A = 0, B = 1 \) → 0** - **\( A = 1, B = 1 \) → 1** If OR is used: - **\( A = 0, B = 0 \) → 0** - **\\( A = 1, B = 0 \) → 1** - **\*( A = 0, B = 1 \) → 1** - **\( A = 1, B = 1 \) → 1** Without specific indications of the logical operations used, two interpretations (AND and OR) can be proposed. However, based on the most likely approach (the logical operation AND), the latter case \( A = 1, B = 1 \) will lead to a true result (1), while all other combinations will lead to a false result (0).
+ - + - - + - + + - + - + - - + + - Subjective Factuality Possible Fedorchenko Mikhail Valerevich Neutral Neutral Neutral
=1
C±D A±B B±D A B C D A±C A+C+D A±B±D A±B±C D±C±B A±D±C±B Syllogism Федорченко Михаил Валерьевич
C -A -B -C A B Syllogism Федорченко Михаил Валерьевич A B c -B -C -A 101 AND 010 = 000 101 OR 010 = 111 101 XOR 010 = 111
Syllogism Федорченко Михаил Валерьевич 1 2 3 4 5 6 7 8 9 10 11 12 2 -> 4 -> 12 -> 24 -> n. Or 2^n
A B C B+C B+A A+C (B+A)+(A+C) (B+A)+(B+C) (B+C)+(A+C) Федорченко Михаил Валерьевич Syllogism
Got it, you've provided sets of values for the variables \(A\), \(B\) and \(C\) (0 or 1), and now you need to determine whether the result is 1 or 0 for each case. Let's look at the basic expressions in the triangle: 1. **(B + A) + (A + C)** 2. **(B + A) + (B + C)** 3. **(B + C) + (A + C)** The value of the expression depends on the values of the variables \(A\), \(B\), and \(C\). ### Logical Operations: - Adding the logical variables \(A + B\) gives 1 if at least one of \(A\) or \(B\) is 1. - If both are 0, the result is 0. - Adding two expressions \(X + Y\) is also 1 if at least one of them is 1. #### Consider each set of values: 1. **\\(A = 0\), \(B = 0\), \(C = 0\)**. - \((B + A) + (A + C) = (0 + 0) + (0 + 0) = 0 + 0 = 0\) - \((B + A) + (B + C) = (0 + 0) + (0 + 0) = 0 + 0 = 0\) - \((B + C) + (A + C) = (0 + 0) + (0 + 0) = 0 + 0 = 0\) - **Result: 0** 2. **\\(A = 1\), \(B = 0\), \(C = 0\)**. - \((B + A) + (A + C) = (0 + 1) + (1 + 0) = 1 + 1 = 1\) - \((B + A) + (B + C) = (0 + 1) + (0 + 0) = 1 + 0 = 1\) - \((B + C) + (A + C) = (0 + 0) + (1 + 0) = 0 + 1 = 1\) - **Result: 1** 3. **\\(A = 0\), \(B = 0\), \(C = 1\)**. - \((B + A) + (A + C) = (0 + 0) + (0 + 1) = 0 + 1 = 1\) - \((B + A) + (B + C) = (0 + 0) + (0 + 1) = 0 + 1 = 1\) - \((B + C) + (A + C) = (0 + 1) + (0 + 1) = 1 + 1 = 1\) - **Result: 1** 4. **\(A = 1\), \(B = 1\), \(C = 0\)**. - \((B + A) + (A + C) = (1 + 1) + (1 + 0) = 1 + 1 = 1\) - \((B + A) + (B + C) = (1 + 1) + (1 + 0) = 1 + 1 = 1\) - \((B + C) + (A + C) = (1 + 0) + (1 + 0) = 1 + 1 = 1\) - **Result: 1** 5. **\(A = 1\), \(B = 0\), \(C = 1\)**. - \((B + A) + (A + C) = (0 + 1) + (1 + 1) = 1 + 1 = 1\) - \((B + A) + (B + C) = (0 + 1) + (0 + 1) = 1 + 1 = 1\) - \((B + C) + (A + C) = (0 + 1) + (1 + 1) = 1 + 1 = 1\) - **Result: 1** 6. **\(A = 1\), \(B = 1\), \(C = 1\)**. - \((B + A) + (A + C) = (1 + 1) + (1 + 1) = 1 + 1 = 1\) - \((B + A) + (B + C) = (1 + 1) + (1 + 1) = 1 + 1 = 1\) - \((B + C) + (A + C) = (1 + 1) + (1 + 1) = 1 + 1 = 1\) - ### Score: 1** ### Totals: For your given sets of variable values \(A\), \(B\), \(C\): - For the set \(0, 0, 0\), the result is 0. - For all other sets ( \(1, 0, 0\); \(0, 1, 0 \); \(0, 0, 1\); \(1, 1, 0\); \(1, 0, 1\); \(1, 1, 1\) ), the result is 1.
https://archive.org/754189189-syllogism-and-syllogistic-syllogistic-intellectus-cognitum/Logic_of_Being-Syllogism-and-Syllogistic-Syllogistic-intellectus-cognitum.pptx https://archive.org/details/logic-of-being-statements
i i i i 1 1 0 1 0->1 …. …. information is generated syllogism correction Game
1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 1 Event Contradict Truth Sum =3 > > = = > > > > > = > > = = > 0 0 0 > = = Viewpoint 1 Viewpoint 2 Viewpoint 3 Viewpoint 4 Viewpoint 5 Viewpoint 6 Viewpoint 8 0 0 0 False Sum = 0 Федорченко Михаил Валерьевич > Conflict 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 = = > Viewpoint 7
West India Russia China World West East West USSR UN West Russia Ukraine West North South East ∴ΩΝ
1 2 3 4 5 6 7 8 9 10 11 12 UN
Israel EU Iran Palestine USA Near East Russia China Solutions to the Middle East conflict.
China Russia NATO USA EU Middle East India SCO CSTO WWIII
West Russia Ukraine 1 1 1 1 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 Decision-making system.
West Russia Ukraine 1 1 1 1 0 0 0 1 0 Sovereignty War Conflict Наиболее вероятное решение согласно построению дерева решений: Сохранение суверенитета Украины с вероятностью 60%, но при этом высока вероятность продолжения конфликта без прямой войны (36%). Прямая война менее вероятна (24%), однако она не исключена в случае эскалации. В случае потери суверенитета, вероятность вмешательства Запада остается на уровне 20%, что может быть сдерживающим фактором для России.
West Russia Ukraine 1 1 1 1 0 0 0 1 1 Sovereignty War Conflict Наиболее вероятное решение согласно построению дерева решений: Вероятность войны: 30% при сохранении суверенитета + 28% при потере = 58%. Вероятность конфликта без прямой войны: 30%. Вероятность ограниченного вмешательства Запада: 12% использовать теорию игр или вероятностного дерева решений
